document.write( "Question 55075This question is from textbook Algebra 2 with trigonometry
\n" ); document.write( ": You are going to invest $25,000.00, part at 14% and part at 16%. What is the most that can be invested at 14% to make at least $3,600.00 interest per year? \n" ); document.write( "
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You are going to invest $25,000.00, part at 14% and part at 16%. What is the most that can be invested at 14% to make at least $3,600.00 interest per year? \r
\n" ); document.write( "\n" ); document.write( "ans: let x be the amount invested at 14%
\n" ); document.write( " and y be the amount invested at 16%\r
\n" ); document.write( "\n" ); document.write( "hence total amount = x+y = 25,000.00 -------- I\r
\n" ); document.write( "\n" ); document.write( " total interest according to the problem will be
\n" ); document.write( " .14*x+.16*y=3,600.00 --------- II\r
\n" ); document.write( "\n" ); document.write( "then value of x to be found out by solving above two equations.
\n" ); document.write( " Multiply eq. I by .16 and subtracting from II Will give\r
\n" ); document.write( "\n" ); document.write( " (.14*x+.16*y)-.16*(x+y)=3600-.16*25000
\n" ); document.write( " .14x-.16x=3600-4000=400
\n" ); document.write( " .02x = 400
\n" ); document.write( " x = 400/.02 =20,000
\n" ); document.write( " hence invested at 14% = $20,000 \n" ); document.write( "
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