document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585091>Question 585091</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For r(x) = 10x^2-19x-5 find all values of r(a)=-11.<BR>\n" );
document.write( "My problem with this is i cannot factorize it. I have gotten to this point:<BR>\n" );
document.write( "r(a)=10a^2-19a-5<BR>\n" );
document.write( "10a^2-19a-5-11<BR>\n" );
document.write( "10a^2-19a+6=0. \r<BR>\n" );
document.write( "\n" );
document.write( "When i multiply 10*-5 i get - 50,  i cannot find factors in that for -19<BR>\n" );
document.write( "I also tried 10*6. The factors i get -15+-4. But when i work the equation and get the answers and plug them into the first problem it does not equal to -11. Please help me. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373093 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not 10a^2-19a-5-11 but<BR>\n" );
document.write( "10a^2-19a-5=-11<BR>\n" );
document.write( "10a^2-19a-5+11=0<BR>\n" );
document.write( "10a^2-19a+6=0<BR>\n" );
document.write( "(2x-3)*(5x-2)=0<BR>\n" );
document.write( "(2x-3)=0<BR>\n" );
document.write( "2x=3<BR>\n" );
document.write( "x=3/2<BR>\n" );
document.write( "(5x-2)=0<BR>\n" );
document.write( "5x=2<BR>\n" );
document.write( "x=2/5<BR>\n" );
document.write( "Both work.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );