document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=584996>Question 584996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ann can jog to work in 2/3 of an hour. When she rides her bike, it takes her 1/4 of an hour. If she rides 11 miles per hour faster than she jogs, how far away is her work?<BR>\n" );
document.write( "Do not do any rounding. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373080 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r*t=d<BR>\n" );
document.write( "2/3*j=1/4*(j+11)\r<BR>\n" );
document.write( "\n" );
document.write( "j=33/5<BR>\n" );
document.write( "2/3*33/5=2/5*33/3=2/5*11=22/5 or 4.4 miles<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );