document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=585077>Question 585077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> lnx-3ln3=3\r<BR>\n" );
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document.write( "ln3x=6\r<BR>\n" );
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document.write( "lne^2/2\r<BR>\n" );
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document.write( "ln(2x-1)=0\r<BR>\n" );
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document.write( "I just don't understand how to work these out. I'd appreciate you help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #373078 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=373078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lnx-3ln3=3<BR>\n" );
document.write( "ln(x) - 3ln(3) = 3<BR>\n" );
document.write( "ln(x) - ln(27) = 3  3^3 = 27<BR>\n" );
document.write( "ln(x/27) = 3 Subtracting exponents --> division (logs are exponents)<BR>\n" );
document.write( "ln(x/27) = ln(e^3)  True of any number<BR>\n" );
document.write( "x/27 = e^3<BR>\n" );
document.write( "x = 27e^3<BR>\n" );
document.write( "x =~ 542.31<BR>\n" );
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document.write( "ln3x=6<BR>\n" );
document.write( "ln(3x) = 6<BR>\n" );
document.write( "Similar to the one above<BR>\n" );
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document.write( "lne^2/2<BR>\n" );
document.write( "= ln(e^2) - ln(2)<BR>\n" );
document.write( "= 2 - ln(2)<BR>\n" );
document.write( "=~ 1.30685<BR>\n" );
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document.write( "ln(2x-1)=0<BR>\n" );
document.write( "If the log = 0, the argument is 1, for any base<BR>\n" );
document.write( "2x-1 = 1<BR>\n" );
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document.write( "Or,<BR>\n" );
document.write( "2x-1 = e^0<BR>\n" );
document.write( " </SPAN>\n" );
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