document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55077>Question 55077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the process to solve  x - 2x = 15  ? Do I have to factor something?<BR>\n" );
document.write( "thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37307 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the process to solve  x - 2x = 15  ? Do I have to factor something?<BR>\n" );
document.write( "No, nothing that complicated.<BR>\n" );
document.write( "First combine your like terms on the left.<BR>\n" );
document.write( "1x-2x=15<BR>\n" );
document.write( "(1-2)x=15<BR>\n" );
document.write( "-1x=15<BR>\n" );
document.write( "Divide by the coefficient of x, -1 on both sides of the equal sign.<BR>\n" );
document.write( "-1x/-1=15/-1<BR>\n" );
document.write( "x=-15<BR>\n" );
document.write( ":<BR>\n" );
document.write( "To check to see if we're right, substitute -15 in where the x's were in the original equation and see if both sides equal.<BR>\n" );
document.write( "(-15)-2(-15)=15<BR>\n" );
document.write( "-15+30=15<BR>\n" );
document.write( "15=15  The answer checks out.<BR>\n" );
document.write( "Happy Calculating!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );