document.write( "Question 584614: A jeweler has four rings, each weighing 20 grams, made of an alloy of 5% silver and 95% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 80%.
\n" ); document.write( "(a) Construct a model that gives the fraction G(x) of the new alloy that is pure gold. (Let x represent the number of grams of silver added.)
\n" ); document.write( "G(x) =
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Algebra.Com's Answer #373052 by ankor@dixie-net.com(22740)\"\" \"About 
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A jeweler has four rings, each weighing 20 grams, made of an alloy of 5% silver and 95% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 80%.
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\n" ); document.write( "Total weight of the 4 rings 80 grams
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\n" ); document.write( "Let x = amt of extra silver required
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\n" ); document.write( "A mixture of gold equation (the amt of gold remains the same only the % changes)
\n" ); document.write( ".95(80) = .80(x+80)
\n" ); document.write( "76 = .80x + 64
\n" ); document.write( "76 - 64 = .8x
\n" ); document.write( "12 = .8x
\n" ); document.write( "x = 12/.8
\n" ); document.write( "x = 15 grams of silver required to reduce gold content to 80%
\n" ); document.write( ":
\n" ); document.write( "(a) Construct a model that gives the fraction G(x) of the new alloy that is pure gold. (Let x represent the number of grams of silver added.)
\n" ); document.write( "G(x) =
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\n" ); document.write( "In the original mixture of 80 gram, 76 grams is pure gold, therefore
\n" ); document.write( "G(x) = \"76%2F%28%28x%2B80%29%29\"
\n" ); document.write( "Check this by adding 15 grams of silver like we did above
\n" ); document.write( "G(x) = \"76%2F%28%2815%2B80%29%29\"
\n" ); document.write( "G(x) = .8 or 8/10 is pure gold
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