document.write( "Question 585027: During a job interview, Pam Thompson is offered a salary of $39,000. The company gives annual raises of 9 percent. What would be Pam’s salary during her fifth year on the job? \n" ); document.write( "

Algebra.Com's Answer #373035 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
After 1st year:
\n" ); document.write( "39k + $\"+.09%2A39000+=+3519+\"$ = 42,510
\n" ); document.write( "After 2nd year:
\n" ); document.write( "42,510 + $\"+.09%2A42510+=+3825.9+\"$ = 46335.90
\n" ); document.write( "The formula for this is:
\n" ); document.write( " $\"+s+=+39000%2A%28+1+%2B+.09+%29%5Ey+\"$
\n" ); document.write( "where $\"y\"$ is the year before the one she's in
\n" ); document.write( "so, if she's in her 3rd year:
\n" ); document.write( " $\"+s+=+39000%2A%28+1+%2B+.09+%29%5E2+\"$
\n" ); document.write( " $\"+s+=+39000%2A1.09%5E2+\"$
\n" ); document.write( " $\"+s+=+39000%2A1.1881+\"$
\n" ); document.write( " $\"+s+=+46335.9+\"$
\n" ); document.write( "So, if she's in her 5th year
\n" ); document.write( " $\"+s+=+39000%2A%28+1+%2B+.09+%29%5E4+\"$
\n" ); document.write( " $\"+s+=+39000%2A1.4115816+\"$
\n" ); document.write( " $\"+s+=+55051.68+\"$
\n" ); document.write( "Her salary during her 5th year is $55,051.68
\n" ); document.write( "I think this is right, but you can get a 2nd opinion, too \n" ); document.write( "

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