document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=584924>Question 584924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one vase contains 3 red, 4 pink and 5 white roses and another vase has 2 red, 2 pink and 2 white roses, what is probability that one rose chosen from each vase will be the same color?  Please explain how to come to the answer.  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372977 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 3 possible scenarios:\r<BR>\n" );
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document.write( "Scenario 1) Both roses are red\r<BR>\n" );
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document.write( "P(Both Red) = P(Red)*P(Red) = (3/12)*(2/6) = 6/72 = 1/12\r<BR>\n" );
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document.write( "Scenario 2) Both roses are pink\r<BR>\n" );
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document.write( "P(Both Pink) = P(Pink)*P(Pink) = (4/12)*(2/6) = 8/72 = 1/9\r<BR>\n" );
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document.write( "Scenario 2) Both roses are white\r<BR>\n" );
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document.write( "P(Both White) = P(White)*P(White) = (5/12)*(2/6) = 10/72 = 5/36\r<BR>\n" );
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document.write( "Now add up all the probabilities:\r<BR>\n" );
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document.write( "1/12 + 1/9 + 5/36 = 3/36 + 4/36 + 5/36 = (3+4+5)/36 = 12/36 = 1/3\r<BR>\n" );
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document.write( "So the probability that one rose chosen from each vase will be the same color is <font color=\"red\">1/3</font> </SPAN>\n" );
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