document.write( "Question 584876: Find the mean, variance,and binomial distribution with the given values of n and p. \r
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document.write( "n=122,p=0.24\r
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document.write( "The mean is: _____ (round to the nearest tenth as needed)
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document.write( "The variance is:_____(round to the nearest tenth as needed)
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document.write( "The standard divination is: _____(round to the nearest tenth as needed) \n" );
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Algebra.Com's Answer #372932 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! Mean: \r \n" ); document.write( "\n" ); document.write( "mu = np = 122*0.24 = 29.28\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the mean is 29.3 (rounded to the nearest tenth)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "Variance:\r \n" ); document.write( "\n" ); document.write( "sigma^2 = np(1-p) = 122*0.24(1-0.24) = 22.2528\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the variance is 22.3 (rounded to the nearest tenth)\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "Standard Deviation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sigma = sqrt(np(1-p)) = sqrt(122*0.24(1-0.24)) = 4.717287\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the standard deviation is 4.7 (rounded to the nearest tenth) \n" ); document.write( " |