document.write( "Question 584800: If you roll a die 60 times what's the probability of landing on a 1 or a 6? How do I explain to a fifth grader how to find the answer. I also need that as a percent and a fraction. \n" ); document.write( "
Algebra.Com's Answer #372902 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
a 1 or a 6 are 1/3 of the 6 faces of a die, so the probability of NOT getting one or the other, on any given roll, is 2/3\r
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\n" ); document.write( "\n" ); document.write( "since each roll is a separate (independent) event
\n" ); document.write( "___the probability of NOT getting a 1 or 6 on 60 rolls is 2/3 times itself, 60 times, (2/3)^60 -- a very small number\r
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\n" ); document.write( "\n" ); document.write( "since an event HAS TO either happen or not happen, the sum of the two probabilities is 1
\n" ); document.write( "___ so the probability of 1 or 6 in 60 rolls is ___ 1 - (2/3)^60\r
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\n" ); document.write( "\n" ); document.write( "this makes sense because it is difficult to imagine rolling a fair die 60 times without getting a 1 or 6\r
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\n" ); document.write( "\n" ); document.write( "1 - [(2/3)^60] = 1 - 2.72x10^-11 = 1 - 0.0000000000272 = 0.9999999999728\r
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\n" ); document.write( "\n" ); document.write( "it would be more than a thousand times easier to win a Powerball jackpot \n" ); document.write( "
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