document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=584793>Question 584793</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two sides of a triangle are equal in length and double the length of the shortest side. The perimeter of the triangle is 36 inches. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372892 by </B><A HREF=/tutors/aboutme.mpl?userid=Schaman_Dempster><B>Schaman_Dempster(26)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Schaman_Dempster><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Schaman_Dempster><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the measures of equal sides be x and the measure of the shortest side be y.\r<BR>\n" );
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document.write( "Also, it is given that the measure of equal sides is double of the shortest side.\r<BR>\n" );
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document.write( "So,   x = 2y        ----------- (1)\r<BR>\n" );
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document.write( "We know that perimeter of triangle is sum of all the three sides.\r<BR>\n" );
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document.write( "Therefore,  x + x + y = 36\r<BR>\n" );
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document.write( "or  2y + 2y + y = 36   {Using equation (1)  x = 2y}<BR>\n" );
document.write( "5y = 36<BR>\n" );
document.write( "y = 36/5\r<BR>\n" );
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document.write( "Using equation (1),<BR>\n" );
document.write( "x = 2y = 2*(36/5) = 72/5\r<BR>\n" );
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document.write( "Hence, the sides of triangle are 72/5, 72/5 and 36/5 </SPAN>\n" );
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