document.write( "Question 584762: The area of the piece is 30 ft². The length is 1 less than 3 times the width. How wide should the metal piece be? Round to the nearest hundredth of a foot. \n" ); document.write( "
Algebra.Com's Answer #372871 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The area of the piece is 30 ft². The length is 1 less than 3 times the width. How wide should the metal piece be? Round to the nearest hundredth of a foot. \n" ); document.write( ". \n" ); document.write( "Let w = width \n" ); document.write( "then \n" ); document.write( "3w-1 = length \n" ); document.write( ". \n" ); document.write( "w(3w-1) = 30 \n" ); document.write( "3w^2-w = 30 \n" ); document.write( "3w^2-w-30 = 0 \n" ); document.write( "replace middle term: \n" ); document.write( "3w^2 +9w-10w -30 = 0 \n" ); document.write( "group terms: \n" ); document.write( "(3w^2+9w) - (10w+30) = 0 \n" ); document.write( "3w(w+3) - 10(w+3) = 0 \n" ); document.write( "(w+3)(3w-10) = 0 \n" ); document.write( "w = {-3, 10/3} \n" ); document.write( "throw out the negative solution (extraneous) leaving: \n" ); document.write( "w = 10/3 \n" ); document.write( "w = 3.33 feet\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |