document.write( "Question 54802: Can someone help me on this problem?\r
\n" ); document.write( "\n" ); document.write( " The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( " Thanks, Ashley
\n" ); document.write( "

Algebra.Com's Answer #37287 by Cintchr(481)\"\" \"About 
You can put this solution on YOUR website!
\"+P=2%28l%2Bw%29+\"
\n" ); document.write( "\"+l+=+2%2Bw+\"
\n" ); document.write( "Substitute the 2nd equation into the first
\n" ); document.write( "\"+P+=2%282%2Bw%2Bw%29+\"
\n" ); document.write( "add like terms
\n" ); document.write( "\"+P+=+2%282+%2B+2w%29+\"
\n" ); document.write( "Distribute the 2
\n" ); document.write( "\"+P+=+4+%2B+4w+\"
\n" ); document.write( "By your problem the Perimiter is 52
\n" ); document.write( "\"+52+=+4+%2B+4w+\"
\n" ); document.write( "subtract 4 from both sides
\n" ); document.write( "\"+48+=+4w+\"
\n" ); document.write( "divvide by 4
\n" ); document.write( "\"+12+=+w+\"
\n" ); document.write( "Substitute 12 back into the 2nd equation
\n" ); document.write( "\"+l+=+2%2Bw+\"
\n" ); document.write( "\"+l+=+2%2B12+\"
\n" ); document.write( "\"+l+=+14+\"
\n" ); document.write( "Dimensions of the rectangle are 12 X 14
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