document.write( "Question 584185: Find the point on the x-axis which is equidistant from (1,2) and (-5, -15) \n" ); document.write( "

Algebra.Com's Answer #372860 by htmentor(1343) $\"\"$ $\"About$

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Since the point is on the x-axis, the y-value is zero, so we can write is as (x,0)
\n" ); document.write( "The squares of the distances from this point to the other points are
\n" ); document.write( "(x-1)^2 + 2^2
\n" ); document.write( "(x+5)^2 + 15^2
\n" ); document.write( "Set them equal and solve for x:
\n" ); document.write( "(x-1)^2 + 2^2 = (x+5)^2 + 15^2
\n" ); document.write( "x^2 - 2x + 5 = x^2 + 10x + 25 + 225
\n" ); document.write( "12x = -245
\n" ); document.write( "x = -245/12 \n" ); document.write( "

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