document.write( "Question 584714: the sum of 2 number is 100. The larger number is 10 more than twice the smaller \n" ); document.write( "

Algebra.Com's Answer #372857 by Schaman_Dempster(26) $\"\"$ $\"About$

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Let x and y be the two numbers whose sum is 100 such that x>y.\r
\n" ); document.write( "\n" ); document.write( "So, x + y = 100 ------------- (1)\r
\n" ); document.write( "\n" ); document.write( "Also, larger number is 10 more than twice the smaller.\r
\n" ); document.write( "\n" ); document.write( "Therefore, x = 2y + 10
\n" ); document.write( " 100 - y = 2y + 10 {Using equation (1) }
\n" ); document.write( "90 = 3y
\n" ); document.write( "Dividing both the sides by 3, we get:\r
\n" ); document.write( "\n" ); document.write( "90/3 = y
\n" ); document.write( "or y = 30\r
\n" ); document.write( "\n" ); document.write( "Plugging back the value of y in equation (1), we get:
\n" ); document.write( "x = 100 - y
\n" ); document.write( "x = 100 -30
\n" ); document.write( "x = 70\r
\n" ); document.write( "\n" ); document.write( "Thus, the larger number is 70 and the smaller number is 30. \n" ); document.write( "

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