document.write( "Question 584716: i have a right angled triangle, a=y b=4y and c=20.6 i need to find y, i keep coming up with the wrong answer, i start with sqrt4*y^2+y^2=20.6 i keep comming up with y =9.21 but that doesent work for 4y? any help is appreciated\r
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Algebra.Com's Answer #372853 by Schaman_Dempster(26) $\"\"$ $\"About$

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\n" ); document.write( "Hello there, I see what you have been missing. I will provide the step by step solution below:\r
\n" ); document.write( "\n" ); document.write( "sqrt(a^2 + b^2) = c
\n" ); document.write( "sqrt( (4y)^2 + y^2 ) = 20.6
\n" ); document.write( "sqrt( 16y^2 + y^2) = 20.6
\n" ); document.write( "sqrt(17 y^2 ) = 20.6
\n" ); document.write( "Squaring on both the sides, we get:
\n" ); document.write( " 17 y^2 = 424.36
\n" ); document.write( "Dividing both the sides by 17, we get:
\n" ); document.write( "y^2 = 424.36/17
\n" ); document.write( "y^2 = 24.96235294117647\r
\n" ); document.write( "\n" ); document.write( "y = 4.996233875748459 , y = - 4.996233875748459
\n" ); document.write( "Since y is the length of one of the sides, it can not hold a negative value.\r
\n" ); document.write( "\n" ); document.write( "Thus, y = 4.996233875748459
\n" ); document.write( "One can round off the answer to 3 decimal places as: y = 4.996 \n" ); document.write( "

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