document.write( "Question 584697: A tugboat can pull a boat 24 mi downstream in 2h.going upstream the tugboat can pull the same boat 16 mi in 2h. what is the speed of the tugboat in still water ? what is the speed of the current ?
\n" ); document.write( "how can use the formula d=rt to help you solve the problem?
\n" ); document.write( "how are the tugboat's speed when traveling upstream and downstream related to its speed in still water and the spend of the current?
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Algebra.Com's Answer #372845 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against wind x-y mph 2 hours
\n" ); document.write( "with wind x+y mph 2 hours
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\n" ); document.write( "Distance upstream= 16 miles Downstream = 24 miles
\n" ); document.write( "t=d/r against current
\n" ); document.write( "16/(x-y )=2
\n" ); document.write( "2(x-y) =16
\n" ); document.write( "2x-2y = 16 ....................1
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\n" ); document.write( "24/(x+y )= 2.00
\n" ); document.write( "2.00(x +y)= 24.00
\n" ); document.write( "2.00x+ 2.00 y =24.00 ...............2
\n" ); document.write( "Multiply (1) by 1
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "we get
\n" ); document.write( "2 x + 2 y = 16
\n" ); document.write( "2 x + 2 y = 24
\n" ); document.write( "4 x = 40
\n" ); document.write( "/ 4
\n" ); document.write( "x = 10.00 mph
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\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2.00 x -2.00 y = 16.00
\n" ); document.write( "20.00 -2.00 y = 16.00
\n" ); document.write( "-2.00 y = 16.00 -20.00
\n" ); document.write( "-2.00 y = -4.00
\n" ); document.write( " y = 2 mph
\n" ); document.write( " Boat 10 mph
\n" ); document.write( " current 2 mph
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