document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=584702>Question 584702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 30 years older than his son, one year ago he was 4 times as old as his son, find their present ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372843 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> son age =x<BR>\n" );
document.write( "father -age = x+30\r<BR>\n" );
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document.write( "last years\r<BR>\n" );
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document.write( "son - age = x-1\r<BR>\n" );
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document.write( "father-age = (x+30)-1= x+29\r<BR>\n" );
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document.write( "(x+29)= 4(x-1)<BR>\n" );
document.write( "x+29 = 4x-4\r<BR>\n" );
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document.write( "4x-x= 29+4<BR>\n" );
document.write( "3x=33\r<BR>\n" );
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document.write( "x= 11 years   son's age\r<BR>\n" );
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document.write( "father's age = 30+11= 41 years </SPAN>\n" );
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