document.write( "Question 584546: how do you find the focus of x^2=16y \n" ); document.write( "

Algebra.Com's Answer #372835 by lwsshak3(11628) $\"\"$ $\"About$

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how do you find the focus of
\n" ); document.write( "x^2=16y
\n" ); document.write( "This is an equation of a parabola that opens upwards of the standard form: (x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex(0,0)
\n" ); document.write( "axis of symmetry: x=0 or y-axis
\n" ); document.write( "4p=16
\n" ); document.write( "p=4
\n" ); document.write( "focus: (0,4) (p units above the vertex on the axis of symmetry) \n" ); document.write( "

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