document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=584656>Question 584656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In this distribution, find the number of kWh that separates the top 55% from the bottom 45%; with a mean of 1050 kWh and and standard deviation of 218 kWh.<BR>\n" );
document.write( "Thanks :-) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372823 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In this distribution, find the number of kWh that separates the top 55% from the bottom 45%; with a mean of 1050 kWh and and standard deviation of 218 kWh.<BR>\n" );
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document.write( "Find the z-value with a left tail of 45%<BR>\n" );
document.write( "invNorm(0.45) = -0.1257<BR>\n" );
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document.write( "# of kWh = -0.1257*218 + 1050 = 1022.61 kWh<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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