document.write( "Question 584651: a boat went 15 miles downstream in 1 hour and then returned to its dock in 5/3 hours. if the current of the stream was constant, find the speed of the boat and speed of the current \n" ); document.write( "
Algebra.Com's Answer #372822 by josmiceli(19441)\"\" \"About 
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Let \"+s+\" = the speed of the boat in still water
\n" ); document.write( "Let \"+c+\" = the speed of the current
\n" ); document.write( "\"+s+%2B+c+\" = the speed of the boat going with the current
\n" ); document.write( "\"+s+-+c+\" = the speed of the boat going against the current
\n" ); document.write( "--------
\n" ); document.write( "(1) \"+15+=+%28+s+%2B+c+%29%2A1+\"
\n" ); document.write( "(2) \"+15+=+%28+s+-+c+%29%2A%285%2F3%29+\"
\n" ); document.write( "---------------------
\n" ); document.write( "(1) \"+s+%2B+c+=+15+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+s+-+c+=+%283%2F5%29%2A15+\"
\n" ); document.write( "(2) \"+s+-+c+=+9+\"
\n" ); document.write( "Add the equations
\n" ); document.write( "(1) \"+s+%2B+c+=+15+\"
\n" ); document.write( "(2) \"+s+-+c+=+9+\"
\n" ); document.write( "\"+2s+=+24+\"
\n" ); document.write( "\"+s+=+12+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+s+%2B+c+=+15+\"
\n" ); document.write( "(1) \"+12+%2B+c+=+15+\"
\n" ); document.write( "(1) \"+c+=+3+\"
\n" ); document.write( "The speed of the boat in still water is 12 mi/hr
\n" ); document.write( "The speed of the current is 3 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+15+=+%28+12+-+3+%29%2A%285%2F3%29+\"
\n" ); document.write( "(2) \"+15+=+9%2A%285%2F3%29+\"
\n" ); document.write( "(2) \"+15+=+15+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );