document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55016>Question 55016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An 80 page newspaper is in one section.  The sheet with page 11 on it is missing.  What other pages are missing? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37282 by </B><A HREF=/tutors/aboutme.mpl?userid=Cintchr><B>Cintchr(481)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cintchr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since each sheet when folded in half would create what looks like a card, it has for pages to it.  The front part of first piece would be pages 1 and 2 while the back part would be pages 79 and 80.\r<BR>\n" );
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document.write( "01 02 ..... 03 04 ....<BR>\n" );
document.write( "80 79 ..... 78 77 ....<BR>\n" );
document.write( "Each pair of pages adds to 81 ... 1+80 .. 2+79 ... 3+78 ... etc.\r<BR>\n" );
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document.write( "Keeping this rule in mind and the fact that page 11 would be the \"front\" of it's sheet (12 would be the other side, just like with pages 1 and 2) we can then find the number that adds to 11 to make 81\r<BR>\n" );
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document.write( "81 - 11 = 70<BR>\n" );
document.write( "81 - 12 = 69\r<BR>\n" );
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document.write( "So the pages that are missing are 11, 12, 70 and 69\r<BR>\n" );
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document.write( " </SPAN>\n" );
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