document.write( "Question 584368: I do not know how to solve this! Please someone show me step by step so I can understand!?!!??!?!??!?\r
\n" ); document.write( "\n" ); document.write( "In 1992, life expectancy of males was 70.7 years. In 1996, it was 74.3 years. Let E represent life expectancy in year t and let t represent the number of years since 1992.
\n" ); document.write( "The linear function E(t) that fits the data is
\n" ); document.write( "E(t) = ? t + ?
\n" ); document.write( "Use the function to predict life expectancy in males in 2007
\n" ); document.write( "E(15)= ?
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Algebra.Com's Answer #372785 by KMST(5328)\"\" \"About 
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Let's say the function is
\n" ); document.write( "\"E%28t%29=mt%2Bb\" and we want to find the numbers m abd b.
\n" ); document.write( "For the year 1992, t=0, because it is 0 years after 1992.
\n" ); document.write( "So \"E%280%29=m-0%2Bb=b=70.7\" gives us \"highligth%28b=70.7%29\"
\n" ); document.write( "For 1996, t=4, because 1996 is 4 years after 1992, and the life expectancy of males is
\n" ); document.write( "\"E%284%29=m%2A4%2B70.7=74.3\"
\n" ); document.write( "That gives us the equation \"4m%2B70.7=74.3\"
\n" ); document.write( "\"4m%2B70.7=74.3\" --> \"4m%2B70.7-70.7=74.3-70.7\" --> \"4m=3.6\" -->
\n" ); document.write( "\"4m%2F4=3.6%2F4\" --> \"highlight%28m=0.9%29\"
\n" ); document.write( "So the function is \"highlight%28E%28t%29=0.9t%2B70.7%29\"
\n" ); document.write( "For 2007, \"t=2007-1992=15\". The life expectancy for males in 2007 can be predicted as
\n" ); document.write( "\"E%2815%29=0.9%2A15%2B70.7=13.5%2B70.7\" --> \"highlight%28E%2815%29=84.2%29\"
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