document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=584364>Question 584364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is confusing. I am not sure how to work this problem step by step. Would Someone please explain this to me?<BR>\n" );
document.write( "Trains A and B are traveling the same direction on parallel tracks. <BR>\n" );
document.write( "Train A is traveling at 80 mph and train B is traveling at 90 mph. <BR>\n" );
document.write( "Train A passes the train station at 12:15 pm. <BR>\n" );
document.write( "If train B passes it at 12:45pm, at what time will train B catch up to train A.<BR>\n" );
document.write( "When will train B catch up to Train A? What time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372762 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The trains leave 30 minutes apart.<BR>\n" );
document.write( "but the second train is going faster.<BR>\n" );
document.write( "80*(x+.5)=90x<BR>\n" );
document.write( "80x+40=90x<BR>\n" );
document.write( "40=10x<BR>\n" );
document.write( "4=x<BR>\n" );
document.write( "They will meet after 4 hours or at 4:15 pm<BR>\n" );
document.write( "80*4.5 =360 miles<BR>\n" );
document.write( "90*4=360 miles<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );