document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=584174>Question 584174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation.x + 2y = 4  x – 5y = 11  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372706 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation.<BR>\n" );
document.write( "x + 2y = 4 <BR>\n" );
document.write( "x – 5y = 11<BR>\n" );
document.write( "---<BR>\n" );
document.write( "1st Eq: x = -2y+4<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Substitute in 2nd:<BR>\n" );
document.write( "-2y+4 - 5y = 11<BR>\n" );
document.write( "==========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );