document.write( "Question 584017: how can you find the focus of this equation y plus 1 over 1 = ( x - 3 over 2 ) squared \n" ); document.write( "
Algebra.Com's Answer #372686 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how can you find the focus of this equation y plus 1 over 1 = ( x - 3 over 2 ) squared \n" ); document.write( "** \n" ); document.write( "(y+1)/1=((x-3)/2)^2 \n" ); document.write( "(y+1)=((x-3)^2/4 \n" ); document.write( "4(y+1)=(x-3)^2 \n" ); document.write( "(x-3)^2=4(y+1) \n" ); document.write( "Standard form of equation for a parabola that opens upwards: \n" ); document.write( "(x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex \n" ); document.write( "For given equation of parabola: (x-3)^2=4(y+1) \n" ); document.write( "vertex: (3,-1) \n" ); document.write( "axis of symmetry: x=-3 \n" ); document.write( "4p=4 \n" ); document.write( "p=1 \n" ); document.write( "focus: (3,-1+p)=(3,-1+1)=(3,0) (p-unit above the vertex on the axis of symmetry)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |