document.write( "Question 584017: how can you find the focus of this equation y plus 1 over 1 = ( x - 3 over 2 ) squared \n" ); document.write( "
Algebra.Com's Answer #372686 by lwsshak3(11628)\"\" \"About 
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how can you find the focus of this equation y plus 1 over 1 = ( x - 3 over 2 ) squared
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\n" ); document.write( "(y+1)/1=((x-3)/2)^2
\n" ); document.write( "(y+1)=((x-3)^2/4
\n" ); document.write( "4(y+1)=(x-3)^2
\n" ); document.write( "(x-3)^2=4(y+1)
\n" ); document.write( "Standard form of equation for a parabola that opens upwards:
\n" ); document.write( "(x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex
\n" ); document.write( "For given equation of parabola: (x-3)^2=4(y+1)
\n" ); document.write( "vertex: (3,-1)
\n" ); document.write( "axis of symmetry: x=-3
\n" ); document.write( "4p=4
\n" ); document.write( "p=1
\n" ); document.write( "focus: (3,-1+p)=(3,-1+1)=(3,0) (p-unit above the vertex on the axis of symmetry)\r
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