document.write( "Question 583603: a cyclist rode the first 36-mile portion of his workout at a constant speed.for the 30-mile cooldown portion of his workout, he reduced his speed by 2 miles per hour. Each portion of the workout took the same time. Find the cyclist's speed during the first portion and find his speed during the cooldown portion. \n" ); document.write( "
Algebra.Com's Answer #372635 by ankor@dixie-net.com(22740)\"\" \"About 
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a cyclist rode the first 36-mile portion of his workout at a constant speed.
\n" ); document.write( "For the 30-mile cooldown portion of his workout, he reduced his speed by 2 miles per hour.
\n" ); document.write( " Each portion of the workout took the same time.
\n" ); document.write( "Find the cyclist's speed during the first portion and find his speed during the cooldown portion.
\n" ); document.write( ":
\n" ); document.write( "let s = his speed on the 1st 36 mi
\n" ); document.write( "then
\n" ); document.write( "(s-2) = his speed on the last 30 mi
\n" ); document.write( ":
\n" ); document.write( "Write time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "workout time = cooldown time
\n" ); document.write( "\"36%2Fs\" = \"30%2F%28s-2%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "36(s-2) = 30s
\n" ); document.write( "36s - 72 = 30s
\n" ); document.write( "36s - 30s = 72
\n" ); document.write( "6s = 72
\n" ); document.write( "s = 12 mph his workout speed
\n" ); document.write( "then
\n" ); document.write( "10 mph his cooldown speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the actual times, they should be equal
\n" ); document.write( "36/12 = 3 hrs
\n" ); document.write( "30/10 = 3 hrs
\n" ); document.write( "
\n" );