document.write( "Question 583796: A point on the circle has coordinates (2,m) write a value for m. Center of circle is at (0,0) and the end points are at (6,0) and (-6,0) \n" ); document.write( "
Algebra.Com's Answer #372599 by jim_thompson5910(35256)\"\" \"About 
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The equation of the circle is \"x%5E2%2By%5E2=6%5E2\" or simply \"x%5E2%2By%5E2=36\". Now plug in x = 2 and solve for y:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2=36\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%5E2%2By%5E2=36\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%2By%5E2=36\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2=36-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2=32\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%22%22%2B-sqrt%2832%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=sqrt%2832%29\" or \"y=-sqrt%2832%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=4%2Asqrt%282%29\" or \"y=-4%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the value of 'm' is \"4%2Asqrt%282%29\" or \"-4%2Asqrt%282%29\"
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\n" ); document.write( "\n" ); document.write( "If you need more help, you can email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "or you can visit my website: http://www.freewebs.com/jimthompson5910/home.html for more details\r
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\n" ); document.write( "\n" ); document.write( "Thank you,\r
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\n" ); document.write( "\n" ); document.write( "Jim
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