document.write( "Question 583763: 5n^2-5n/3n-3 \n" ); document.write( "
Algebra.Com's Answer #372574 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%285n%5E2-5n%29%2F%283n-3%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%285n%28n-1%29%29%2F%283n-3%29\" Factor the numerator\r
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\n" ); document.write( "\n" ); document.write( "\"%285n%28n-1%29%29%2F%283%28n-1%29%29\" Factor the denominator\r
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\n" ); document.write( "\n" ); document.write( "\"%285n%2Across%28%28n-1%29%29%29%2F%283%2Across%28%28n-1%29%29%29\" Cancel out the common terms\r
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\n" ); document.write( "\n" ); document.write( "\"%285n%29%2F3\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So \"%285n%5E2-5n%29%2F%283n-3%29\" completely simplifies to \"%285n%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%285n%5E2-5n%29%2F%283n-3%29=%285n%29%2F3\" for all values of 'n' where \"n%3C%3E1\"\r
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