document.write( "Question 583736: An airplane with a speed of 160 knots is headed east while a 24-knot wind is blowing from 240. Find the course and round to the nearest degree. \n" ); document.write( "
Algebra.Com's Answer #372569 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! An airplane with a speed of 160 knots is headed east while a 24-knot wind is blowing from 240. Find the course and round to the nearest degree. \n" ); document.write( "--------------- \n" ); document.write( "The vectors make a triangle with 160 on the base, a 150 deg angle and the 24 side. If you plot it on the x-y plane with the plane's speed from (0,0) to (160,0) and the wind vector starting at (160,0) length 24, the internal angle is 150 degs. \n" ); document.write( "----------- \n" ); document.write( "find the 3rd side: \n" ); document.write( " \n" ); document.write( "r =~ 181.18 knots (the plane's groundspeed) \n" ); document.write( "-------- \n" ); document.write( "Use the Sine Law to find the angle at the origin: \n" ); document.write( "181.18/sin(150) = 24/sin(A) \n" ); document.write( "sin(A) = 24*sin(150)/181.18 \n" ); document.write( "A =~ 3.8 degs --> 4 degs \n" ); document.write( "------ \n" ); document.write( "The course = 090 - 4 = 086 \n" ); document.write( "----------------- \n" ); document.write( "Note: East is 090 degs heading, and the angles increase clockwise \n" ); document.write( "The plane is flying a heading of 090 @ 160 knots \n" ); document.write( "Winds are 240 @ 24 kts. \n" ); document.write( "\"Winds are two-four-zero at two-four.\" is what is said. \n" ); document.write( " \n" ); document.write( " |