document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=583727>Question 583727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of an angle is fourteen times the measure of a complementary angle. What is the measure of each angle?<BR>\n" );
document.write( "How do I even begin! I understand that a complementary angle equals 90', and that 14x90=1260...but I have to find two angle measurements....do i divide it in half? HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372565 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measure of an angle is fourteen times the measure of a complementary angle. What is the measure of each angle?<BR>\n" );
document.write( "How do I even begin! I understand that a complementary angle equals 90', and that 14x90=1260...but I have to find two angle measurements....do i divide it in half?<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=an angle<BR>\n" );
document.write( "90-x=complement of the angle<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x=14(90-x)<BR>\n" );
document.write( "x=1490-14x<BR>\n" );
document.write( "15x=1490<BR>\n" );
document.write( "x=84º (measure of angle)<BR>\n" );
document.write( "90-x=90-84=6º (measure of angle's complement)<BR>\n" );
document.write( "Check: 84º is 14 times 6º </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );