document.write( "Question 583689: Can you please help me solve this? I am supposed to solve and state whether the binomial is a factor of the polynomial.\r
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document.write( "I used synthetic division to drop the coefficients and got: \r
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document.write( "2] 16 -32 0 0 -81 162
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document.write( " 0 32 0 0 0 -162
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document.write( " 16 0 0 0 0 -81 0
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document.write( "(The zeroes in the top row are because there are no x-cubed and x-squared variables, therefore they're respresented by a zero, right?)\r
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document.write( "Multiple choice allowed me the answers of:
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document.write( "A - 1348; no
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document.write( "B - 0; yes
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document.write( "C - 700; yes
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document.write( "D - 0; no\r
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document.write( " I am pretty sure the answer is C because my remainder is zero, and x-2 is a factor of the original equation. If this is not right, can you please show me what I've done wrong?
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document.write( "(Also, I apologize if the synthetic division does not line up properly when submitted and if it makes it harder for you to read.) \n" );
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Algebra.Com's Answer #372537 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "No. Not answer C.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The numeric part of the answer is supposed to be the remainder that results from the synthetic division which is the same as the value of the function evaluated at the divisor. That is, if your function is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |