document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=583570>Question 583570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A biologist has a 30% solution and a 5% solution of the same plant nutrient. How many cubic centimeters (cc) of each solution should be mixed to obtain a 25 cc of a 25% solution? (Round your answers to 2 decimal places if needed) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372510 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A biologist has a 30% solution and a 5% solution of the same plant nutrient. How many cubic centimeters (cc) of each solution should be mixed to obtain a 25 cc of a 25% solution? (Round your answers to 2 decimal places if needed)<BR>\n" );
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document.write( "Let x = amount (cc) of 30% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "25-x = amount (cc) of 5% solution<BR>\n" );
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document.write( ".30x + .05(25-x) = .25(25)<BR>\n" );
document.write( ".30x + 1.25-.05x = 6.25<BR>\n" );
document.write( ".25x + 1.25 = 6.25<BR>\n" );
document.write( ".25x = 5<BR>\n" );
document.write( "x = 20 cc (of 30% solution)<BR>\n" );
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document.write( "amount of 5% solution:<BR>\n" );
document.write( "25-x = 25-20 = 5 cc\r<BR>\n" );
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