document.write( "Question 583572: A 20% iodine solution is mixed with a 70% iodine solution to produce 5 gallons of 50% Iodine solution. How many gallons of each solution are needed? \n" ); document.write( "
Algebra.Com's Answer #372507 by nerdybill(7384)\"\" \"About 
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A 20% iodine solution is mixed with a 70% iodine solution to produce 5 gallons of 50% Iodine solution. How many gallons of each solution are needed?
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\n" ); document.write( "Let x = amount (gallons) of 20% solution
\n" ); document.write( "then
\n" ); document.write( "5-x = amount (gallons) of 70% solution
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\n" ); document.write( ".20x + .70(5-x) = .50(5)
\n" ); document.write( ".20x + 3.5-.70x = 2.5
\n" ); document.write( "3.5-.50x = 2.5
\n" ); document.write( "-.50x = -1
\n" ); document.write( "x = -1/(-.50)
\n" ); document.write( "x = 2 gallons (of 20% solution)
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\n" ); document.write( "70% solution:
\n" ); document.write( "5-x = 5-2 = 3 gallons
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