document.write( "Question 583572: A 20% iodine solution is mixed with a 70% iodine solution to produce 5 gallons of 50% Iodine solution. How many gallons of each solution are needed? \n" ); document.write( "
Algebra.Com's Answer #372507 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A 20% iodine solution is mixed with a 70% iodine solution to produce 5 gallons of 50% Iodine solution. How many gallons of each solution are needed? \n" ); document.write( ". \n" ); document.write( "Let x = amount (gallons) of 20% solution \n" ); document.write( "then \n" ); document.write( "5-x = amount (gallons) of 70% solution \n" ); document.write( ". \n" ); document.write( ".20x + .70(5-x) = .50(5) \n" ); document.write( ".20x + 3.5-.70x = 2.5 \n" ); document.write( "3.5-.50x = 2.5 \n" ); document.write( "-.50x = -1 \n" ); document.write( "x = -1/(-.50) \n" ); document.write( "x = 2 gallons (of 20% solution) \n" ); document.write( ". \n" ); document.write( "70% solution: \n" ); document.write( "5-x = 5-2 = 3 gallons \n" ); document.write( " \n" ); document.write( " |