document.write( "Question 583461: Find a general form of an equation for the perpendicular bisector of the segment AB. A(4,-4),B(-2,4) \n" ); document.write( "
Algebra.Com's Answer #372454 by mananth(16946)\"\" \"About 
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x1 y1 x2 y2
\n" ); document.write( "4 -4 -2 4
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( 4 - -4 )/( -2 - 4 )
\n" ); document.write( "( 8 / -6 )
\n" ); document.write( "m= -4/3 \r
\n" ); document.write( "\n" ); document.write( "The slope of a perpendicular line will be the negative reciprocal of this slope
\n" ); document.write( "=3/4\r
\n" ); document.write( "\n" ); document.write( "slope = 3/4 and it passes through the midpoint of the above two points\r
\n" ); document.write( "\n" ); document.write( "mid point formula
\n" ); document.write( "x= (x1+x2)/2 = (4-2)/2=1
\n" ); document.write( "y=0\r
\n" ); document.write( "\n" ); document.write( "the point is (1,0)\r
\n" ); document.write( "\n" ); document.write( "slope = 3/4, point = (1,0)\r
\n" ); document.write( "\n" ); document.write( "substitute in y=mx+b\r
\n" ); document.write( "\n" ); document.write( "0=3/4 *1+b
\n" ); document.write( "b=-3/4\r
\n" ); document.write( "\n" ); document.write( "the equation is y=(3/4)x-3/4
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