document.write( "Question 583444: the length of each leg of an isosceles triangle is 5 centemeters more than twice the length of the base. if the perimeter of this isosceles triangle is 95 centemeters, what is the length of the base?.
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Algebra.Com's Answer #372449 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! the length of each leg of an isosceles triangle is 5 centemeters more than twice the length of the base. if the perimeter of this isosceles triangle is 95 centemeters, what is the length of the base?. \n" ); document.write( "-- \n" ); document.write( "Let base length be \"x\". \n" ); document.write( "Each leg is \"2x+5\" \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "x + 2(2x+5) = 95 \n" ); document.write( "x + 4x + 10 = 95 \n" ); document.write( "5x = 85 \n" ); document.write( "x = 17 cm (base length) \n" ); document.write( "2x+5 = 39 cm (length of each base) \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H \n" ); document.write( "================ \n" ); document.write( " |