document.write( "Question 583444: the length of each leg of an isosceles triangle is 5 centemeters more than twice the length of the base. if the perimeter of this isosceles triangle is 95 centemeters, what is the length of the base?.
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Algebra.Com's Answer #372449 by stanbon(75887)\"\" \"About 
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the length of each leg of an isosceles triangle is 5 centemeters more than twice the length of the base. if the perimeter of this isosceles triangle is 95 centemeters, what is the length of the base?.
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\n" ); document.write( "Let base length be \"x\".
\n" ); document.write( "Each leg is \"2x+5\"
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\n" ); document.write( "Equation:
\n" ); document.write( "x + 2(2x+5) = 95
\n" ); document.write( "x + 4x + 10 = 95
\n" ); document.write( "5x = 85
\n" ); document.write( "x = 17 cm (base length)
\n" ); document.write( "2x+5 = 39 cm (length of each base)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H
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