document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=583180>Question 583180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mixture problem=  A 55 gallon barrel contains a mixture with a concentration of 40%. How much of this mixture must be withdrawn and replaced by 100% concentrate to bring up the mixture up to 75% concentration. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372441 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372441\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 55 gallon barrel contains a mixture with a concentration of 40%.<BR>\n" );
document.write( " How much of this mixture must be withdrawn and replaced by 100% concentrate to bring up the mixture up to 75% concentration.<BR>\n" );
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document.write( "Let x = amt of 100% stuff required, and the amt of 40% mixture to be removed<BR>\n" );
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document.write( ".40(55-x) + x = .75(55)<BR>\n" );
document.write( "22 - .4x + x = 41.25<BR>\n" );
document.write( ".6x = 41.25 - 22<BR>\n" );
document.write( ".6x = 19.25<BR>\n" );
document.write( "x = 19.25/,6<BR>\n" );
document.write( "x = 32.1 mixture removed, then 32.1 gal of 100% added to replace it </SPAN>\n" );
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