document.write( "Question 583399: It takes three hours to drive to a city. If you had driven 10 mph slower it would have taken 36 minutes longer. How far did you drive? \"I am a little confused because I thought I would need more information to solve a problem like this one. I thought at first to do this: 3 hours 3 hours 36 minutes, then have something else on the bottom of one to compare them to, but there is nothing, except I arrived at the city??????????\" \n" ); document.write( "
Algebra.Com's Answer #372430 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
It takes three hours to drive to a city.
\n" ); document.write( " If you had driven 10 mph slower it would have taken 36 minutes longer.
\n" ); document.write( " How far did you drive?
\n" ); document.write( ":
\n" ); document.write( "Change 36 min to hrs: 36/60 = .6 hr
\n" ); document.write( ":
\n" ); document.write( "First find the speed; then we can find the distance
\n" ); document.write( ":
\n" ); document.write( "s = the actual speed
\n" ); document.write( "then
\n" ); document.write( "(s-10) = the slower speed
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "slow speed dist = actual speed distance
\n" ); document.write( "3.6(s-10) = 3s
\n" ); document.write( "3.6s - 36 = 3s
\n" ); document.write( "3.6s - 3s = 36
\n" ); document.write( ".6s = 36
\n" ); document.write( "s = 36/.6
\n" ); document.write( "s = 60 mph is the speed
\n" ); document.write( ":
\n" ); document.write( "Now find the distance:
\n" ); document.write( "3 * 60 = 180 mi
\n" ); document.write( ":
\n" ); document.write( "Check the distance using the slower speed, it should be the same
\n" ); document.write( "3.6 * 50 = 180 mi\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );