document.write( "Question 583348: It has to be 2 feet high, and the width is to be 3 feet less than its length. If it needs to hold a volume of 80 cubic feet, find the length and width of the box \n" ); document.write( "
Algebra.Com's Answer #372422 by mananth(16946)![]() ![]() You can put this solution on YOUR website! length =x \n" ); document.write( "width = x-3\r \n" ); document.write( "\n" ); document.write( "height = 2\r \n" ); document.write( "\n" ); document.write( "Volume = L*W*H\r \n" ); document.write( "\n" ); document.write( "x(x-3)*2= 80 \n" ); document.write( "2x^2-6x=80\r \n" ); document.write( "\n" ); document.write( "2x^2-6x-80=0\r \n" ); document.write( "\n" ); document.write( "/2 \n" ); document.write( "x^2-3x-40=0 \n" ); document.write( "x^2-8x+5x-40=0 \n" ); document.write( "x(x-8)+5(x-8)=0 \n" ); document.write( "(x-8)(x+5)=0 \n" ); document.write( "x= 8 which is positive\r \n" ); document.write( "\n" ); document.write( "L= 8 feet \n" ); document.write( "W = 3 less = 5 feet \n" ); document.write( " |