document.write( "Question 583247: How to find the end behavior of this function?\r
\n" ); document.write( "\n" ); document.write( "x(2-x)(x+3)^2\r
\n" ); document.write( "\n" ); document.write( "would it be: as x approaches positive or negative infinity, y approaches negative infinity?
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Algebra.Com's Answer #372396 by lwsshak3(11628)\"\" \"About 
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How to find the end behavior of this function?
\n" ); document.write( "x(2-x)(x+3)^2
\n" ); document.write( "**
\n" ); document.write( "zeros are: 0, 2 and -3 (multi 2)
\n" ); document.write( "Draw a number line with the zeros on it to show how the sign of f(x) changes as we go thru the zeros.\r
\n" ); document.write( "\n" ); document.write( "<..-...-3....-.....0.....+....2....-....>\r
\n" ); document.write( "\n" ); document.write( "When x is >2, f(x)<0
\n" ); document.write( "Moving to the left, signs of the intervals switch as we go thru zeros of odd multiplicity like 1, 3, 5 etc. but do not switch when going thru zeros of even multiplicity like 2, 4, 6 etc. For this problem, 3 is of even multiplicity 2, while 0 and 2 are of odd multiplicity 1.
\n" ); document.write( "You are right that as x approaches negative or positive infinity, f(x) approaches negative infinity.
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