document.write( "Question 583198: Question: Use the Rational Zeros Theorem to find all the real zeros of the polynomial function \"f%28x%29+=+x%5E4+-+x%5E3-6x%5E2%2B4x%2B8\". Use the zeros to factor f over the real numbers.\r
\n" ); document.write( "\n" ); document.write( "I know the possible factors of the constant are 1, 2, 4, 8, -1, -2, -4, -8. But using the remainder theorem, none of them are actually possible factors (none of those factors have a remainder of 0). But when I graph it on a graphing calculator, there are zeros (x-intercepts). So I'm a little confused here. Thank you.
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Algebra.Com's Answer #372389 by lwsshak3(11628)\"\" \"About 
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Question: Use the Rational Zeros Theorem to find all the real zeros of the polynomial function
\n" ); document.write( "f(x) = x^4 - x^3-6x^2+4x+8. Use the zeros to factor f over the real numbers.
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\n" ); document.write( "Rational Roots Theorem:
\n" ); document.write( "Using synthetic division:
\n" ); document.write( "...0....|.....1....-1.......-6.......4.....8
\n" ); document.write( "...1....|.....1.....0.......-6.....-2....-8
\n" ); document.write( "...2....|.....1.....1........-4....-4......0 (2 is a zero)
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\n" ); document.write( "..,,0...|.....1..... 1......-4......-4
\n" ); document.write( "..-1...|.....1......0.......-5......4
\n" ); document.write( "..-2...|.....1.....-1.......-2.....0 (-2 is a zero)
\n" ); document.write( "f(x)=(x-2)(x+2)(x^2-x-2)
\n" ); document.write( "f(x)=(x-2)(x+2)(x-2)(x+1)
\n" ); document.write( "Zeros: -2, -1, & 2 (multiplicity 2)
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