document.write( "Question 583198: Question: Use the Rational Zeros Theorem to find all the real zeros of the polynomial function $\"f%28x%29+=+x%5E4+-+x%5E3-6x%5E2%2B4x%2B8\"$ . Use the zeros to factor f over the real numbers.\r
\n" ); document.write( "\n" ); document.write( "I know the possible factors of the constant are 1, 2, 4, 8, -1, -2, -4, -8. But using the remainder theorem, none of them are actually possible factors (none of those factors have a remainder of 0). But when I graph it on a graphing calculator, there are zeros (x-intercepts). So I'm a little confused here. Thank you. \n" ); document.write( "

Algebra.Com's Answer #372380 by scott8148(6628) $\"\"$ $\"About$

You can put this solution on YOUR website!
-2 works , so you need to check your calculations to find others \n" ); document.write( "

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