document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=55023>Question 55023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brendi,Nicki sell memberships in an automobile club over the telephone. Brenda sells one membership every 0.125 hour and nicki sells one membership every 0.1 hour. At what rate ( in memberships per hour) are the memberships being sold when both are working? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37236 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If Brenda sells 1 membership every 0.125 hour, then she sells 1/0.125 memberships in 1 hour.  1/0.125 = 8 memberships per hour.<BR>\n" );
document.write( "If Nicki sells 1 membership every 0.1 hour, then she sells 1/0.1 memberships in 1 hour. 1/0.1 = 10 memberships per hour.<BR>\n" );
document.write( "Together, Brenda & Nicki sell 8 + 10 = 18 memberships per hour. </SPAN>\n" );
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