document.write( "Question 583089: A box of coins containing dimes and nickels totaling $7.35. If there are 12 more dimes than nickels, how many of each type are in the box? \n" ); document.write( "

Algebra.Com's Answer #372322 by JBarnum(2146) $\"\"$ $\"About$

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dimes are .10 nickels are .05
\n" ); document.write( " $\".1d%2B.05n=7.35\"$
\n" ); document.write( " $\"n%2B12=d\"$
\n" ); document.write( " $\".1%28n%2B12%29%2B.05n=7.35\"$
\n" ); document.write( " $\".1n%2B1.2%2B.05n=7.35\"$
\n" ); document.write( " $\".15n=6.15\"$
\n" ); document.write( " $\"n=41\"$
\n" ); document.write( " $\"d=53\"$
\n" ); document.write( "check
\n" ); document.write( " $\".1d%2B.05n=7.35\"$
\n" ); document.write( " $\".1%2853%29%2B.05%2841%29=7.35\"$
\n" ); document.write( " $\"5.3%2B2.05=7.35\"$
\n" ); document.write( " $\"7.35=7.35\"$
\n" ); document.write( "correct \n" ); document.write( "

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