document.write( "Question 582880: need to come up with two equations, with x and y\r
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\n" ); document.write( "\n" ); document.write( "A bricklayer lays an average of 150 bricks per hour. During a job, he is called away and replaced by a less experienced man, who averages 120 bricks per hour. The two men laid 930 bricks in 7 hours. How long did each work?
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Algebra.Com's Answer #372270 by ankor@dixie-net.com(22740)\"\" \"About 
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A bricklayer lays an average of 150 bricks per hour.
\n" ); document.write( " During a job, he is called away and replaced by a less experienced man, who averages 120 bricks per hour.
\n" ); document.write( " The two men laid 930 bricks in 7 hours. How long did each work?
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\n" ); document.write( "Let x = time worked by the experienced bricklayer
\n" ); document.write( "Let y = time worked by apprentice
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\n" ); document.write( "Time equation
\n" ); document.write( "x + y = 7
\n" ); document.write( "y = (7-x); use this form for substitution
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\n" ); document.write( "Production equation
\n" ); document.write( "150x + 120y = 930
\n" ); document.write( "replace y with (7-x), find x
\n" ); document.write( "150x + 120(7-x) = 930
\n" ); document.write( "150x + 840 - 120x = 930
\n" ); document.write( "150x - 120x = 930 - 840
\n" ); document.write( "30x = 90
\n" ); document.write( "x = 90/30
\n" ); document.write( "x = 3 hrs worked the exp guy
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\n" ); document.write( "You can find the hrs worked by the other guy. check solutions in the production equation
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