document.write( "Question 54773: Please help me solve:\r
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Algebra.Com's Answer #37227 by Edwin McCravy(20056) $\"\"$ $\"About$
You can put this solution on YOUR website!
Please help me solve: \r\n" );
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document.write( "(5x) + 6 > 3x\r\n" );
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document.write( "On the left side of the equation,  get rid of any term that\r\n" );
document.write( "DOES NOT contain an x and you KEEP anything that DOES contain x.\r\n" );
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document.write( "On the right side it's the other way around.  You have to get \r\n" );
document.write( "rid of anything that DOES NOT contain x and KEEP anything that \r\n" );
document.write( "DOES contain x. \r\n" );
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document.write( "The terms on the left are \"(3x)\", and \"+ 6,\"\r\n" );
document.write( "Get rid of the + 6 because that does not contain an x\r\n" );
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document.write( "There is only one term on the right, \"3x\". It DOES contain an x\r\n" );
document.write( "so you want to get rid of it.\r\n" );
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document.write( "But we will get rid of the 6 on the left first.\r\n" );
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document.write( "To do that we add its opposite \"- 6\" to both sides. \r\n" );
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document.write( "Add \"- 6\" to the left side by putting the \"- 6\" underneath the \r\n" );
document.write( "\"+ 6\" on the left.  There are no terms wiuthout x on the right\r\n" );
document.write( "side so just add it by writing it far to the right. Then draw a \r\n" );
document.write( "line and add vertically:\r\n" );
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document.write( "(5x) + 6 > 3x\r\n" );
document.write( "     - 6      - 6  \r\n" );
document.write( "-----------------\r\n" );
document.write( "(5x)     > 3x - 6\r\n" );
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document.write( "There is really no need for those parentheses, so we can just \r\n" );
document.write( "take them off\r\n" );
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document.write( "5x > 3x - 6\r\n" );
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document.write( "Now we have no more terms on the left that DO NOT contain x. So we \r\n" );
document.write( "look at the right side.  It contains as its only term 3x, and that \r\n" );
document.write( "has an x in it.  So wew get rid of it by adding its opposite to both \r\n" );
document.write( "sides.\r\n" );
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document.write( " 5x > 3x - 6\r\n" );
document.write( "-3x  -3x\r\n" );
document.write( "------------\r\n" );
document.write( " 2x >    - 6\r\n" );
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document.write( "Now we only need to get rid of the 2 coefficient of x, \r\n" );
document.write( "so that we'll just have x left.  We get rid of a coefficient \r\n" );
document.write( "by dividing both sides by it. So w divide both sides by 2:\r\n" );
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document.write( " 2x     - 6 \r\n" );
document.write( "---- > ------ \r\n" );
document.write( "  2      2 \r\n" );
document.write( "  \r\n" );
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document.write( "Now the 2'a cancel on the left, and on the right the 2 \r\n" );
document.write( "cancels into the 6 and we get - 3.\r\n" );
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document.write( " 1      - 3\r\n" );
document.write( " 2x     - 6 \r\n" );
document.write( "---- > ------ \r\n" );
document.write( "  2       \r\n" );
document.write( "  1      1\r\n" );
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document.write( "So you just have \r\n" );
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document.write( "   x > -3\r\n" );
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document.write( "It's just like an equation. But if we had divided by \r\n" );
document.write( "a negative we would have had to reverse the inequality. But we \r\n" );
document.write( "divided by a positive (positive 2, that is), so we did not rever\r\n" );
document.write( "the inequality symbol. But in another problem you will have to \r\n" );
document.write( "reverse the inequality, just not in this one.  You reverse the\r\n" );
document.write( "inequality ONLY when you didvide by a NEGATIVE NUMBER\r\n" );
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document.write( "Edwin
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