document.write( "Question 582824: An investment of 62,000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned 8% interest the second 6% and the third 9%. The total interest from the investment was 4740. The interest from the first investment was 6 times the interest from the second. Find the amounts of the three parts of the investments \n" ); document.write( "
Algebra.Com's Answer #372260 by mananth(16946)![]() ![]() You can put this solution on YOUR website! An investment of 62,000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned 8% interest the second 6% and the third 9%. The total interest from the investment was 4740. The interest from the first investment was 6 times the interest from the second. Find the amounts of the three parts of \r \n" ); document.write( "\n" ); document.write( "partI x 8 % \n" ); document.write( "part II y 6 % \n" ); document.write( "part III z 9 % \n" ); document.write( "Total Investment=$ 62000 \n" ); document.write( "Total interest from all =$4740 \n" ); document.write( "Interest from Part I is 6 times interest from Part II \n" ); document.write( " \n" ); document.write( "Interest from part II = 0.06 y \n" ); document.write( "Interest from partI = 0.08 x \n" ); document.write( "Interest from part III = 0.09 z \n" ); document.write( "0.08 x = 6 * 0.06 y \n" ); document.write( "0.08 x = 0.36 y \n" ); document.write( "x= 4.5y \n" ); document.write( " \n" ); document.write( "0.06 y + 0.08 x + 0.09 z = 4740 \n" ); document.write( "But 0.08 x = 0.36 y \n" ); document.write( "0.06 y + 0.36 y + 0.09 z = 4740\r \n" ); document.write( "\n" ); document.write( "0.42 y + 0.09 z= 4740 -------------- 1 \n" ); document.write( " \n" ); document.write( "Investment at \n" ); document.write( "x+y+z= 62000 x=4.5y \n" ); document.write( " \n" ); document.write( "4.5y+y +z= 62000 \n" ); document.write( "5.5y+z =62000 --------------2 \n" ); document.write( " \n" ); document.write( "0.42 y + 0.09 z = 4740 .............1 \n" ); document.write( "5.5 y + 1.00 z = 62000 .............2 \n" ); document.write( "Eliminate z \n" ); document.write( "multiply (1)by -1 \n" ); document.write( "Multiply (2) by 0.09 \n" ); document.write( " \n" ); document.write( "-0.42 y -0.09 z = -4740 \n" ); document.write( "0.5 y + 0.09 z = 5580 \n" ); document.write( "Add the two equations \n" ); document.write( "0.08y =840 \n" ); document.write( "/0.08 \n" ); document.write( "y = 11200.00 \n" ); document.write( "plug value of y In (2) \n" ); document.write( "5.5 y + 1 z = 62000 \n" ); document.write( "61600 + 1 z = 62000 \n" ); document.write( " 1 z = 62000-61600 \n" ); document.write( " 1 z = 400 \n" ); document.write( " z = 400 \n" ); document.write( " \n" ); document.write( "x+y+z= 62000 \n" ); document.write( " \n" ); document.write( "x= 62000 -(11200 +400) \n" ); document.write( "x= 50400 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( " \n" ); document.write( " amount Rate Interest \n" ); document.write( "x = 50400 - 8%-- 4032 \n" ); document.write( "y= 11200 -6%-- 672 \n" ); document.write( "z= 400 -9%-- 36 \n" ); document.write( "Total 62000 -- 4740 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |