document.write( "Question 582240: solve for x using trigonometry for the interval [0, 2π)
\n" ); document.write( "sin^2x= 1/2
\n" ); document.write( "The x after the 2 is NOT a part of the exponent.
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Algebra.Com's Answer #372243 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"%28sin%28x%29%29%5E2=1%2F2\"
\n" ); document.write( "There is a positive and a negative value for \"sin%28x%29\".
\n" ); document.write( "The positive solution is:
\n" ); document.write( "The negative solution is: \"sin%28x%29=-sqrt%281%2F2%29=-sqrt%282%29%2F2=sin%285pi%2F4%29=sin%287pi%2F4%29\"
\n" ); document.write( "Those four angles \"pi%2F4\", \"3pi%2F4\", \"5pi%2F4\" and \"7pi%2F4\" are the solution.
\n" ); document.write( "The reference angle is \"pi%2F4\", or \"45%5Eo\" for those allergic to \"pi\".
\n" ); document.write( "For each (first quadrant) reference angle there is, in each of the other quadrants, a \"reflection\" angle that has the same absolute value for all trigonometric functions. It is \"pi-angle\", the reflection on the y axis, for the second quadrant. It is \"pi%2Bangle\", the reflection on the origin, for the third quadrant, and \"-angle\", or \"2pi-angle\" if you want it positive, the reflection on the x axis, for the third quadrant.
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