document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=582707>Question 582707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4(2n-3)+1 fing the compostion </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372188 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4(2n-3)+1 find the compostion<BR>\n" );
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document.write( "There is more than one way to answer this.<BR>\n" );
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document.write( "Here is one way:<BR>\n" );
document.write( "Let g(x) = 2x-3<BR>\n" );
document.write( "Let f(x) = 4x+1<BR>\n" );
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document.write( "Then f[g(x)] = f[2x-3) = 4(2x-3)+1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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