document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=582657>Question 582657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of twie a first number and three times a second number is 67. if the second number is subtracted from the three times the first number the result is 7. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372184 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the numbers be x & y\r<BR>\n" );
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document.write( "2x+3y=67.............(1)\r<BR>\n" );
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document.write( "3x-y=7.............(2)<BR>\n" );
document.write( "multiply equation by 3<BR>\n" );
document.write( "9x-3y=21\r<BR>\n" );
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document.write( "add to equation (1)<BR>\n" );
document.write( "11x=88<BR>\n" );
document.write( "/11<BR>\n" );
document.write( "x=8 \r<BR>\n" );
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document.write( "plug value of x in (1)\r<BR>\n" );
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document.write( "2x+3y=67<BR>\n" );
document.write( "16+3y=67<BR>\n" );
document.write( "3y=51<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "y=17  </SPAN>\n" );
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